x + {A} = 90º       <DEF + <ABC = 90º

   - {A}       {A}         Subtract {A} from both sides

x = {=90-A}          <DEF = {B}º

The sum of complementary angles equals 90 degrees.
The sum of supplementary angles equals 180 degrees.

x + {A} = 180º       <DEF + <ABC = 180º

   - {A}       {A}         Subtract {A} from both sides

x = {=180-A}          <DEF = {B}º

x + {A} = 180º       <DEF + <ABC = 180º

   - {A}       {A}         Subtract {A} from both sides

x = {=180-A}          <DEF = {B}º

Two angles are supplementary angles if the sum of the angles equals one hundred eighty degrees.

Two angles are complementary angles if the sum of the angles equals ninety degrees.

To plot a point: Start at the Origin: (0,0)

1.  The X value determines how far left or right the point is.
• If X is positive, move to the right
• If X is negative, move to the left

2. The Y value determines how far up or down the point is.

• If Y is positive, move up
• If Y is negative, move down

To plot a point: Start at the Origin: (0,0)

1.  The X value determines how far left or right the point is.
• If X is positive, move to the right
• If X is negative, move to the left

2. The Y value determines how far up or down the point is.

• If Y is positive, move up
• If Y is negative, move down

on the order you divided the prime numbers.

Here are two possible solutions.

on the order you divided the prime numbers.

Here are two possible solutions.

{expression}

{prime1} • {prime2} • {var1} • {var2}

{expression}

{prime1} • {prime2}  • {var1} • {var1} • {var2}

It is standard practice to write the variables in alphabetical order.  

(The computer will mark the answer wrong it the variables
are not in alphabetical order even though the products are equal.)

{var1}² ={var1} • {var1}  

{number}

/\

 {=prime[0]}

{=prime[1]}

{number}

/\

{option}

{=number/option}

/\

/\

{=prime[0]}    {=prime[1]}

{prime[2]}    {=prime[3]}

{number}

/\

{option}

{=number/option}

/\

/\

{=prime[0]}    {=prime[1]}

{prime[2]}    {=prime[3]}

{number}

/\

{option}

{=number/option}

/\

/\

{=prime[0]}    {=prime[1]}

{prime[2]}    {=prime[3]}

{number}

/\

{option}

{=number/option}

/\

/\

{=prime[0]}    {=prime[1]}

{prime[2]}    {=prime[3]}

{number}

/\

{option}

{=number/option}

/\

/\

{=prime[0]}    {=prime[1]}

{prime[2]}    {=prime[3]}

Composite Numbers: 4,  6, 8, 9, 10, 12,14, 15, 16, 18, 20, 21, 22, 24, 25

Neither: 1

There can be more than mode.   All ages that occur {mode} times is a mode. 

The mode is {mode} because it occurs {times} times.  

There can be more than mode.   All ages that occur {mode} times is a mode. 

Find the sum of the ages, then divide by the number of youth.

The sum: {sumAges}

The number of youth: 50

{sumAges} ÷ 50 = {mean}