There is one {roll} on the six sided die. The probability is \(\frac{1}{6}\).
| Area = \(\pi\) radius2 | The Formula for Area | |
| Area = (3.14)({radius})2 | Substitute the known values: Use \(\pi\) = 3.14 radius={radius} | |
| Area = (3.14)({=radius*radius}) | Calculate ({radius})2 ({radius})2=({radius})({radius}) = {=radius*radius} | |
| Area = {area} {unit}2 | Multiply (3.14)({=radius*radius}) | |
| *** Remember that Area is square units |
| Area = \(\pi\) radius2 | The Formula for Area | |
| Area = (3.14)({radius})2 | Substitute the known values: Use \(\pi\) = 3.14 radius={radius} | |
| Area = (3.14)({=radius*radius}) | Calculate ({radius})2 ({radius})2=({radius})({radius}) = {=radius*radius} | |
| Area = {area} {unit}2 | Multiply (3.14)({=radius*radius}) | |
| *** Remember that Area is square units |
The area of the circle={_0}{_1:units:MCE}
]]>| Circumference = \(\pi\) diameter | The Formula for Circumference | |
| C = (3.14)({diameter}) | Substitute the known values: Use \(\pi\) = 3.14 diameter={diameter} | |
| C = {cir} {unit} | Multiply (3.14)({diameter}) | |
| Circumference = \(\pi\) diameter | The Formula for Circumference | |
| C = (3.14)({diameter}) | Substitute the known values: Use \(\pi\) = 3.14 diameter={diameter} | |
| C = {cir} {unit} | Multiply (3.14)({diameter}) | |
| Circumference = \(\pi\) diameter | The Formula for Circumference |
|
| C = (3.14)({diameter}) | Substitute the known values: Use \(\pi\) = 3.14 diameter={diameter} |
|
| C = {cir} {unit} | Multiply (3.14)({diameter}) |
|
The circumference of the circle is {_0}{_1:units:MCE}
]]>| Circumference = \(\pi\) diameter | The Formula for Circumference |
|
| C = (3.14)({diameter}) | Substitute the known values: Use \(\pi\) = 3.14 diameter={diameter} |
|
| C = {cir} {unit} | Multiply (3.14)({diameter}) |
|
The circumference of the circle is {_0}{_1:units:MCE}
]]>| Circumference = 2\(\pi\) radius | The Formula for Circumference | |
| C = (2)(3.14)({radius}) | Substitute the known values: Use \(\pi\) = 3.14 radius={radius} | |
| C = (3.14)({diameter}) | Multiply (2)({radius}) = {diameter} | |
| C = {cir} {unit} | Multiply (3.14)({diameter}) | |
| Circumference = 2\(\pi\) radius | The Formula for Circumference | |
| C = (2)(3.14)({radius}) | Substitute the known values: Use \(\pi\) = 3.14 radius={radius} | |
| C = (3.14)({diameter}) | Multiply (2)({radius}) = {diameter} | |
| C = {cir} {unit} | Multiply (3.14)({diameter}) | |
| Circumference = 2\(\pi\) radius | The Formula for Circumference |
|
| C = (2)(3.14)({radius}) | Substitute the known values: Use \(\pi\) = 3.14 radius={radius} |
|
| C = (3.14)({diameter}) | Multiply (2)({radius}) = {diameter} |
|
| C = {cir} {unit} | Multiply (3.14)({diameter}) |
|
The circumference of the circle= {_0}{_1:units:MCE}
]]>| Circumference = 2\(\pi\) radius | The Formula for Circumference |
|
| C = (2)(3.14)({radius}) | Substitute the known values: Use \(\pi\) = 3.14 radius={radius} |
|
| C = (3.14)({diameter}) | Multiply (2)({radius}) = {diameter} |
|
| C = {cir} {unit} | Multiply (3.14)({diameter}) |
|
The circumference of the circle= {_0}{_1:units:MCE}
]]>| Area = \(\pi\) radius2 | The Formula for Area | |
| Area = (3.14)({radius})2 | Substitute the known values: Use \(\pi\) = 3.14 diameter = {diameter}, therefore calculate the radius. Radius = \(\frac{1}{2}\) of the diameter = (\(\frac{1}{2}\))({diameter})={radius} | |
| Area = (3.14)({=radius*radius}) | Calculate ({radius})2 ({radius})2=({radius})({radius}) = {=radius*radius} | |
| Area = {area} {unit}2 | Multiply (3.14)({=radius*radius}) | |
| *** Remember that Area is square units |
r= \(\frac{1}{2}\)d
r= \(\frac{1}{2}\)){diameter})
r={radius}
]]>| f(x)={function} | given | |
| f({x1})=2({x1}) | Substitute x={x1} | |
| f({x1}) = {y1} | Simplify | |
| f(x)={function} | given | |
| f({x1})=2({x1}) | Substitute x={x1} | |
| f({x1}) = {y1} | Simplify | |
| f(x)={function} | given | |
| f({x1})=2({x1}) | Substitute x={x1} | |
| f({x1}) = {y1} | Simplify | |
| f(x)={function} | given | |
| f({x1})=|{x1}| | Substitute x={x1} | |
| f({x1}) = {y1} | Simplify | |
| f(x)={function} | given | |
| f({x1})=|{x1}| | Substitute x={x1} | |
| f({x1}) = {y1} | Simplify |{x1}| = {y1} because {x1} is {y1} from 0 | |
| f(x)={function} | given | |
| f({x1})=|{x1}| | Substitute x={x1} | |
| f({x1}) = {y1} | Simplify | |
| f(x)={function} | given | |
| f({x1})=({x1})2 | Substitute x={x1} | |
| f({x1}) = {=x1*x1} | Simplify | |
| f(x)={function} | given | |
| f({x2})=({x2})2 | Substitute x={x2} | |
| f({x2}) = {=x2*x2} | Simplify | |
| f(x)={function} | given | |
| f({x3})=({x3})2 | Substitute x={x3} | |
| f({x3}) = {=x3*x3} | Simplify | |
| f(x)={function} | given | |
| f({x1})=({x1})2 | Substitute x={x1} | |
| f({x1}) = {=x1*x1} | Simplify | |
| f(x)={function} | given | |
| f({x2})=({x2})2 | Substitute x={x2} | |
| f({x2}) = {=x2*x2} | Simplify | |
| f(x)={function} | given | |
| f({x3})=({x3})2 | Substitute x={x3} | |
| f({x3}) = {=x3*x3} | Simplify | |
f(x)={function}
f({x1})={function1}
f({x1})={=x1*x1} {bPart}
f({x1})={y1}
]]>x={x2}
f(x)={function}
f({x2})={function2}
f({x2})={=x2*x2} {bPart}
f({x2})={y2}
x={x3}
f(x)={function}
f({x3})={function3}
f({x3})=({=x3*x3}) {bPart}
f({x3})={y3}
To graph the translation of the quadrilateral {xMove} and {yMove}.
point A is at ({Xa1},{Ya1}) therefore the translation is at ({Xa},{Ya}).
point B is at ({Xb1},{Yb1}) therefore the translation is at ({Xb},{Yb}).
point C is at ({Xc1},{Yc1}) therefore the translation is at ({Xc},{Yc}).
point D is at ({Xd1},{Yd1}) therefore the translation is at ({Xd},{Yd}).
To graph the translation of the quadrilateral {xMove} and {yMove}.
point A is at ({Xa1},{Ya1}) therefore the translation is at ({Xa},{Ya}).
point B is at ({Xb1},{Yb1}) therefore the translation is at ({Xb},{Yb}).
point C is at ({Xc1},{Yc1}) therefore the translation is at ({Xc},{Yc}).
point D is at ({Xd1},{Yd1}) therefore the translation is at ({Xd},{Yd}).
To graph the translation of the quadrilateral {xMove} and {yMove}.
point A is at ({Xa1},{Ya1}) therefore the translation is at ({Xa},{Ya}).
point B is at ({Xb1},{Yb1}) therefore the translation is at ({Xb},{Yb}).
point C is at ({Xc1},{Yc1}) therefore the translation is at ({Xc},{Yc}).
point D is at ({Xd1},{Yd1}) therefore the translation is at ({Xd},{Yd}).
To graph the translation of the quadrilateral {xMove} and {yMove}.
point A is at ({Xa1},{Ya1}) therefore the translation is at ({Xa},{Ya}).
point B is at ({Xb1},{Yb1}) therefore the translation is at ({Xb},{Yb}).
point C is at ({Xc1},{Yc1}) therefore the translation is at ({Xc},{Yc}).
point D is at ({Xd1},{Yd1}) therefore the translation is at ({Xd},{Yd}).
To graph the translation of the quadrilateral {xMove} and {yMove}.
point A is at ({Xa1},{Ya1}) therefore the translation is at ({Xa},{Ya}).
point B is at ({Xb1},{Yb1}) therefore the translation is at ({Xb},{Yb}).
point C is at ({Xc1},{Yc1}) therefore the translation is at ({Xc},{Yc}).
point D is at ({Xd1},{Yd1}) therefore the translation is at ({Xd},{Yd}).
To graph the translation of the quadrilateral {xMove} and {yMove}.
point A is at ({Xa1},{Ya1}) therefore the translation is at ({Xa},{Ya}).
point B is at ({Xb1},{Yb1}) therefore the translation is at ({Xb},{Yb}).
point C is at ({Xc1},{Yc1}) therefore the translation is at ({Xc},{Yc}).
point D is at ({Xd1},{Yd1}) therefore the translation is at ({Xd},{Yd}).
To graph the translation of the quadrilateral {xMove} and {yMove}.
point A is at ({Xa1},{Ya1}) therefore the translation is at ({Xa},{Ya}).
point B is at ({Xb1},{Yb1}) therefore the translation is at ({Xb},{Yb}).
point C is at ({Xc1},{Yc1}) therefore the translation is at ({Xc},{Yc}).
point D is at ({Xd1},{Yd1}) therefore the translation is at ({Xd},{Yd}).
To graph the translation of the quadrilateral {xMove} and {yMove}.
point A is at ({Xa1},{Ya1}) therefore the translation is at ({Xa},{Ya}).
point B is at ({Xb1},{Yb1}) therefore the translation is at ({Xb},{Yb}).
point C is at ({Xc1},{Yc1}) therefore the translation is at ({Xc},{Yc}).
point D is at ({Xd1},{Yd1}) therefore the translation is at ({Xd},{Yd}).
To graph the translation of the quadrilateral {xMove} and {yMove}.
point A is at ({Xa1},{Ya1}) therefore the translation is at ({Xa},{Ya}).
point B is at ({Xb1},{Yb1}) therefore the translation is at ({Xb},{Yb}).
point C is at ({Xc1},{Yc1}) therefore the translation is at ({Xc},{Yc}).
point D is at ({Xd1},{Yd1}) therefore the translation is at ({Xd},{Yd}).
To graph the translation of the quadrilateral {xMove} and {yMove}.
point A is at ({Xa1},{Ya1}) therefore the translation is at ({Xa},{Ya}).
point B is at ({Xb1},{Yb1}) therefore the translation is at ({Xb},{Yb}).
point C is at ({Xc1},{Yc1}) therefore the translation is at ({Xc},{Yc}).
point D is at ({Xd1},{Yd1}) therefore the translation is at ({Xd},{Yd}).
To graph the translation of the quadrilateral {xMove} and {yMove}.
point A is at ({Xa1},{Ya1}) therefore the translation is at ({Xa},{Ya}).
point B is at ({Xb1},{Yb1}) therefore the translation is at ({Xb},{Yb}).
point C is at ({Xc1},{Yc1}) therefore the translation is at ({Xc},{Yc}).
point D is at ({Xd1},{Yd1}) therefore the translation is at ({Xd},{Yd}).
To graph the translation of the quadrilateral {xMove} and {yMove}.
point A is at ({Xa1},{Ya1}) therefore the translation is at ({Xa},{Ya}).
point B is at ({Xb1},{Yb1}) therefore the translation is at ({Xb},{Yb}).
point C is at ({Xc1},{Yc1}) therefore the translation is at ({Xc},{Yc}).
point D is at ({Xd1},{Yd1}) therefore the translation is at ({Xd},{Yd}).
To graph the translation of the quadrilateral {xMove} and {yMove}.
point A is at ({Xa1},{Ya1}) therefore the translation is at ({Xa},{Ya}).
point B is at ({Xb1},{Yb1}) therefore the translation is at ({Xb},{Yb}).
point C is at ({Xc1},{Yc1}) therefore the translation is at ({Xc},{Yc}).
point D is at ({Xd1},{Yd1}) therefore the translation is at ({Xd},{Yd}).
To graph the translation of the quadrilateral {xMove} and {yMove}.
point A is at ({Xa1},{Ya1}) therefore the translation is at ({Xa},{Ya}).
point B is at ({Xb1},{Yb1}) therefore the translation is at ({Xb},{Yb}).
point C is at ({Xc1},{Yc1}) therefore the translation is at ({Xc},{Yc}).
point D is at ({Xd1},{Yd1}) therefore the translation is at ({Xd},{Yd}).
|
{offset}{name} {addon} {=ineq[ans]} {=(number1*offset)+addSubt} |
Given | |
| {FBaddonSign} {FBaddonSign} | {FBaddon} |
|
| {offset}{name} {=ineq[ans]} {=(number1*offset)} |
||
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{offset} {offset} |
Divide both sides by {offset} | |
|
{name} {=ineq[ans]} {number1} |
Simplify | |
Check the answer |
||
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{offset}{name} {=ineq[ans]} {=number1*offset} |
Given | |
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({offset})({test}) {=ineq[ans]} {=number1*offset} |
The inequality is {=ineq[ans]} so choose a number {FBp1} {number1}. In the example I will use {test} as your substitution. |
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{=test*offset} {=ineq[ans]} {=number1*offset} |
Simplify Since it is a true statement, the solution is correct. |
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{name}÷{offset} {addon} {=ineq[ans]} {=(number1/offset)+addSubt} |
Given | |
| {FBaddonSign} {FBaddonSign} | {FBaddon} | |
| {name}÷{offset} {=ineq[ans]} {=number1/offset} | ||
|
x {offset} x{offset} |
Multiply both sides by {offset} | |
|
{name} {=ineq[ans]} {number1} |
Simplify | |
Check the answer |
||
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{name}÷{offset} {addon} {=ineq[ans]} {=(number1/offset)+addSubt} |
Given | |
|
({test})÷({offset}) {addon} {=ineq[ans]} {=(number1/offset)+addSubt} |
The inequality is {=ineq[ans]} so choose a number {FBp1} {number1}. In the example I will use {test} as your substitution. |
|
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{=(test/offset)} {addon} {=ineq[ans]} {=(number1/offset)+addSubt} |
Simplify |
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{=(test/offset)+addSubt} {=ineq[ans]} {=(number1/offset)+addSubt} |
Since it is a true statement, the solution is correct. |
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\(\frac{{name}}{{offset}}\) {addon} {=ineq[ans]} {=(number1/offset)+addSubt} |
Given | |
| {FBaddonSign} {FBaddonSign} | {FBaddon} | |
| \(\frac{{name}}{{offset}}\) {=ineq[ans]} {=number1/offset} | ||
|
x {offset} x{offset} |
Multiply both sides by {offset} | |
|
{name} {=ineq[ans]} {number1} |
Simplify | |
Check the answer |
||
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\(\frac{{name}}{{offset}}\) {addon} {=ineq[ans]} {=(number1/offset)+addSubt} |
Given | |
|
\(\frac{{test}}{{offset}}\) {addon} {=ineq[ans]} {=(number1/offset)+addSubt} |
The inequality is {=ineq[ans]} so choose a number {FBp1} {number1}. In the example I will use {test} as the substitution. |
|
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{=(test/offset)} {addon} {=ineq[ans]} {=(number1/offset)+addSubt} |
Simplify |
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{=(test/offset)+addSubt} {=ineq[ans]} {=(number1/offset)+addSubt} |
Since it is a true statement, the solution is correct. |
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What is the probability of landing on {shadeColor}? |
{_0} |
{_1} |
The fraction of the circle shaded {shadeColor} is \(\frac{{num}}{{den}}\).
{FB1}
What is the probability of landing on {shadeColor2}? | {_0} |
{_1} |
The fraction of the circle shaded {shadeColor2} is \(\frac{{num2}}{{den}}\).
{FB2}
There {isAre} {ans} section to land on a {randSpin}.
There are {sections} sections on the spinner.
]]>The probability of landing on a {randSpin} for the next spin is \(\frac{{ans}}{{sections}}\).
There {isAre} {ans} section to land on a {randSpin}.
There are {sections} sections on the spinner.
There {isAre} {ans} section to land on {randSpin}.
There are {sections} sections on the spinner.
]]>The probability of landing on a {randSpin} for the next spin is \(\frac{{ans}}{{sections}}\).
There {isAre} {ans} section to land on {randSpin}.
There are {sections} sections on the spinner.
There {isAre} {ans} section to land on a {randSpin}.
There are {sections} sections on the spinner.
]]>The probability of landing on a {randSpin} for the next spin is \(\frac{{ans}}{{sections}}\).
There {isAre} {ans} section to land on a {randSpin}.
There are {sections} sections on the spinner.
There is one {roll} on the six sided die. The probability is \(\frac{1}{6}\).
There is one {roll} on the six sided die. The probability is \(\frac{1}{6}\).
There is one {roll} on the six sided die. The probability is \(\frac{1}{6}\).
Correct, there {isAre} {ans} {evenOdd} number{s} on the six sided die. The probability is \(\frac{{ans}}{6}\).
Reduce the fraction: \(\frac{{ans}}{6}\) = \(\frac{1}{2}\)
There {isAre} {ans} {evenOdd} number{s} on the six sided die. The probability is \(\frac{{ans}}{6}\).
Reduce the fraction: \(\frac{{ans}}{6}\) = \(\frac{1}{2}\)
{FB}
There {isAre} {ans} numbers greater than {roll} on the six sided die. The probability is \(\frac{{ans}}{6}\).
There {isAre} {ans} numbers less than {roll} on the six sided die. The probability is \(\frac{{ans}}{6}\).
Reduce the fraction: \(\frac{{ans}}{6}\) = {=fractions[ans-1]}
]]>There {isAre} {ans} number{s} less than {roll} on the six sided die. The probability is \(\frac{{ans}}{6}\).
Reduce the fraction: \(\frac{{ans}}{6}\) = {=Rfractions[ans]}
Reduce the fraction: \(\frac{{ans}}{6}\) = {=fractions[ans-1]}
]]>There {isAre} {ans} number{s} less than {roll} on the six sided die. The probability is \(\frac{{ans}}{6}\).
Reduce the fraction: \(\frac{{ans}}{6}\) = {=Rfractions[ans]}
Correct, there {isAre} {ans} number{s} greater than {roll} on the six sided die. The probability is \(\frac{{ans}}{6}\).
Reduce the fraction: \(\frac{{ans}}{6}\) = {=fractions[ans-1]}
{FB}
There {isAre} {ans} number{s} greater than {roll} on the six sided die. The probability is \(\frac{{ans}}{6}\).
Reduce the fraction: \(\frac{{ans}}{6}\) = {=Rfractions[ans]}
{FB}
{FB2}
]]>{FB}
There {isAre} {ans} possible totals of {roll} on two six-sided dice. The probability is \(\frac{{num}}{{den}}\).
{FB2}
]]>{FB}
{FB2}
]]>{FB}
There {isAre} {ans} possible totals of {roll} on two six-sided dice. The probability is \(\frac{{num}}{{den}}\).
{FB2}
]]>{FB}
{FB2}
]]>{FB}
There {isAre} {ans} possible totals of {roll} on two six-sided dice. The probability is \(\frac{{num}}{den}\).
{FB2}
]]>{FB}
{FB2}
]]>{FB}
There {isAre} {ans} possible totals of {roll} on two six-sided dice. The probability is \(\frac{{num}}{{den}}\).
{FB2}
]]>{FB}
{FB2}
]]>{FB}
There {isAre} {ans} possible totals greater than {roll} on two six-sided dice. The probability is \(\frac{{num}}{den}\).
{FB2}
]]>{FB}
{FB2}
]]>{FB}
There {isAre} {ans} possible totals of {roll} on two six-sided dice. The probability is \(\frac{{num}}{{den}}\).
{FB2}
]]>{FB}
{FB2}
]]>{FB}
There {isAre} {ans} possible totals less than {roll} on two six-sided dice. The probability is \(\frac{{num}}{den}\).
{FB2}
]]>The probability of picking {=ques[randQues]} from the word {word} is \(\frac{{ans}}{{numLetters}}\). There {isAre} {ans} {=ques[randQues]}{s} out of {numLetters} letters.
The probability of picking {=ques[randQues]} from the word {word} is \(\frac{{ans}}{{numLetters}}\). There {isAre} {ans} {=ques[randQues]}{s} out of {numLetters} letters.
The probability of picking {=ques[randQues]} from the word {word} is \(\frac{{ans}}{{numLetters}}\). There {isAre} {ans} {=ques[randQues]}{s} out of {numLetters} letters.
{FB}
]]>The probability of picking {=ques[randQues]} from the word {word} is \(\frac{{ans}}{{numLetters}}\). There {isAre} {ans} {=ques[randQues]}{s} out of {numLetters} letters.
The probability of picking {=ques[randQues]} from the word {word} is \(\frac{{ans}}{{numLetters}}\). There {isAre} {ans} {=ques[randQues]}{s} out of {numLetters} letters.
The probability of picking {=ques[randQues]} from the word {word} is \(\frac{{ans}}{{numLetters}}\). There {isAre} {ans} {=ques[randQues]}{s} out of {numLetters} letters.
The probability of picking {=ques[randQues]} from the word {word} is \(\frac{{ans}}{{numLetters}}\). There {isAre} {ans} {=ques[randQues]}{s} out of {numLetters} letters.
{FB}
]]>The probability of picking {=ques[randQues]} from the word {word} is \(\frac{{ans}}{{numLetters}}\). There {isAre} {ans} {=ques[randQues]}{s} out of {numLetters} letters.
The probability of picking {=ques[randQues]} from the word {word} is \(\frac{{ans}}{{numLetters}}\). There {isAre} {ans} {=ques[randQues]}{s} out of {numLetters} letters.
There {isAre} {ans} section to land on a {randSpin}.
There are {sections} sections on the spinner.
]]>The probability of landing on a {randSpin} for the next spin is \(\frac{{ans}}{{sections}}\).
There {isAre} {ans} section to land on a {randSpin}.
There are {sections} sections on the spinner.
The probability of picking {=ques[randQues]} from the word {word} is \(\frac{{ans}}{{numLetters}}\). There {isAre} {ans} {=ques[randQues]}{s} out of {numLetters} letters.
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{_0:choices:MCE} |
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{_0:choices:MCE} |
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{_0:choices:MCE} |
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{_0:choices:MCE} |
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{_0:choices:MCE} |
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{_0:choices:MCE} |
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{_0:choices:MCE} |
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{_0:choices:MCE} |
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{_0:choices:MCE} |
Circumference of a circle = 2\(\pi\)r Circumference is the distance around the circle.
]]>Area of a circle = \(\pi\)r2 Area is the amount of square units inside of the circle.
Circumference of a circle = 2\(\pi\)r Circumference is the distance around the circle.
All the other sections have chosen other choices, therefore there are {numB} students in total that {begin} {titleB}.
All the other sections have chosen other choices, therefore there are {numB} students in total that {begin} {titleB}.
All the other sections have chosen other choices, therefore there are {numB} students in total that {begin} {titleB}.
All the other sections have chosen other choices, therefore there are {numB} students in total that {begin} {titleB}.
All the other sections have chosen other choices, therefore there are {numB} students in total that {begin} {titleB}.
All the other sections have chosen other choices, therefore there are {numB} students in total that {begin} {titleB}.